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1354210981213 is a prime number
BaseRepresentation
bin10011101101001101010…
…000111011010101011101
311210110110021212122010011
4103231031100323111131
5134141411002344323
62514041013043221
7166560416262316
oct23551520732535
94713407778104
101354210981213
11482354881802
1219a556626511
139a9173b920c
144978926d60d
152535d31820d
hex13b4d43b55d

1354210981213 has 2 divisors, whose sum is σ = 1354210981214. Its totient is φ = 1354210981212.

The previous prime is 1354210981183. The next prime is 1354210981243. The reversal of 1354210981213 is 3121890124531.

It is a balanced prime because it is at equal distance from previous prime (1354210981183) and next prime (1354210981243).

It can be written as a sum of positive squares in only one way, i.e., 1328721900804 + 25489080409 = 1152702^2 + 159653^2 .

It is a cyclic number.

It is not a de Polignac number, because 1354210981213 - 25 = 1354210981181 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1354210981243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677105490606 + 677105490607.

It is an arithmetic number, because the mean of its divisors is an integer number (677105490607).

Almost surely, 21354210981213 is an apocalyptic number.

It is an amenable number.

1354210981213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1354210981213 is an equidigital number, since it uses as much as digits as its factorization.

1354210981213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 40.

The spelling of 1354210981213 in words is "one trillion, three hundred fifty-four billion, two hundred ten million, nine hundred eighty-one thousand, two hundred thirteen".