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135432210031 is a prime number
BaseRepresentation
bin111111000100001100…
…0111000011001101111
3110221120111121002212221
41332020120320121233
54204331121210111
6142114450140211
712533064535246
oct1761030703157
9427514532787
10135432210031
1152488a51a08
12222b7b81667
13ca044418b1
1467aab1795d
1537c9be2371
hex1f8863866f

135432210031 has 2 divisors, whose sum is σ = 135432210032. Its totient is φ = 135432210030.

The previous prime is 135432209999. The next prime is 135432210079. The reversal of 135432210031 is 130012234531.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 135432210031 - 25 = 135432209999 is a prime.

It is a super-2 number, since 2×1354322100312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 135432209978 and 135432210005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135432210131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67716105015 + 67716105016.

It is an arithmetic number, because the mean of its divisors is an integer number (67716105016).

Almost surely, 2135432210031 is an apocalyptic number.

135432210031 is a deficient number, since it is larger than the sum of its proper divisors (1).

135432210031 is an equidigital number, since it uses as much as digits as its factorization.

135432210031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 135432210031 its reverse (130012234531), we get a palindrome (265444444562).

The spelling of 135432210031 in words is "one hundred thirty-five billion, four hundred thirty-two million, two hundred ten thousand, thirty-one".