Base | Representation |
---|---|
bin | 111111000100001100… |
… | …0111000011001101111 |
3 | 110221120111121002212221 |
4 | 1332020120320121233 |
5 | 4204331121210111 |
6 | 142114450140211 |
7 | 12533064535246 |
oct | 1761030703157 |
9 | 427514532787 |
10 | 135432210031 |
11 | 52488a51a08 |
12 | 222b7b81667 |
13 | ca044418b1 |
14 | 67aab1795d |
15 | 37c9be2371 |
hex | 1f8863866f |
135432210031 has 2 divisors, whose sum is σ = 135432210032. Its totient is φ = 135432210030.
The previous prime is 135432209999. The next prime is 135432210079. The reversal of 135432210031 is 130012234531.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 135432210031 - 25 = 135432209999 is a prime.
It is a super-2 number, since 2×1354322100312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 135432209978 and 135432210005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135432210131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67716105015 + 67716105016.
It is an arithmetic number, because the mean of its divisors is an integer number (67716105016).
Almost surely, 2135432210031 is an apocalyptic number.
135432210031 is a deficient number, since it is larger than the sum of its proper divisors (1).
135432210031 is an equidigital number, since it uses as much as digits as its factorization.
135432210031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 135432210031 its reverse (130012234531), we get a palindrome (265444444562).
The spelling of 135432210031 in words is "one hundred thirty-five billion, four hundred thirty-two million, two hundred ten thousand, thirty-one".
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