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13550111 is a prime number
BaseRepresentation
bin110011101100…
…001000011111
3221111102020222
4303230020133
511432100421
61202231555
7223113461
oct63541037
927442228
1013550111
117715443
1246555bb
132a65723
141b2a131
1512c9cab
hexcec21f

13550111 has 2 divisors, whose sum is σ = 13550112. Its totient is φ = 13550110.

The previous prime is 13550107. The next prime is 13550123. The reversal of 13550111 is 11105531.

It is a weak prime.

It is an emirp because it is prime and its reverse (11105531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13550111 - 22 = 13550107 is a prime.

It is a super-2 number, since 2×135501112 = 367211016224642, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13550111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13555111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6775055 + 6775056.

It is an arithmetic number, because the mean of its divisors is an integer number (6775056).

Almost surely, 213550111 is an apocalyptic number.

13550111 is a deficient number, since it is larger than the sum of its proper divisors (1).

13550111 is an equidigital number, since it uses as much as digits as its factorization.

13550111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 75, while the sum is 17.

The square root of 13550111 is about 3681.0475411220. The cubic root of 13550111 is about 238.4044097705.

Adding to 13550111 its reverse (11105531), we get a palindrome (24655642).

The spelling of 13550111 in words is "thirteen million, five hundred fifty thousand, one hundred eleven".