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135501230677 is a prime number
BaseRepresentation
bin111111000110010000…
…0001011001001010101
3110221202022110201102011
41332030200023021111
54210001303340202
6142125353344221
712534563312521
oct1761440131125
9427668421364
10135501230677
1152513a0416a
1222317108071
13ca15829707
1467b5d62d81
1537d0cc7bd7
hex1f8c80b255

135501230677 has 2 divisors, whose sum is σ = 135501230678. Its totient is φ = 135501230676.

The previous prime is 135501230621. The next prime is 135501230701. The reversal of 135501230677 is 776032105531.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 135452705521 + 48525156 = 368039^2 + 6966^2 .

It is an emirp because it is prime and its reverse (776032105531) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135501230677 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135501230077) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67750615338 + 67750615339.

It is an arithmetic number, because the mean of its divisors is an integer number (67750615339).

Almost surely, 2135501230677 is an apocalyptic number.

It is an amenable number.

135501230677 is a deficient number, since it is larger than the sum of its proper divisors (1).

135501230677 is an equidigital number, since it uses as much as digits as its factorization.

135501230677 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 132300, while the sum is 40.

The spelling of 135501230677 in words is "one hundred thirty-five billion, five hundred one million, two hundred thirty thousand, six hundred seventy-seven".