1355240405021 has 2 divisors, whose sum is σ = 1355240405022. Its totient is φ = 1355240405020.

The previous prime is 1355240405017. The next prime is 1355240405023. The reversal of 1355240405021 is 1205040425531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1012869139396 + 342371265625 = 1006414^2 + 585125^2 .

It is a cyclic number.

It is not a de Polignac number, because 1355240405021 - 2² = 1355240405017 is a prime.

It is a super-3 number, since 3×1355240405021³ (a number of 37 digits) contains 333 as substring.

Together with 1355240405023, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1355240405023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677620202510 + 677620202511.

It is an arithmetic number, because the mean of its divisors is an integer number (677620202511).

Almost surely, 2^{1355240405021} is an apocalyptic number.

It is an amenable number.

1355240405021 is a deficient number, since it is larger than the sum of its proper divisors (1).

1355240405021 is an equidigital number, since it uses as much as digits as its factorization.

1355240405021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24000, while the sum is 32.

The spelling of 1355240405021 in words is "one trillion, three hundred fifty-five billion, two hundred forty million, four hundred five thousand, twenty-one".