Base | Representation |
---|---|
bin | 11001001111100101… |
… | …00000011000011111 |
3 | 1021222111022221201022 |
4 | 30213302200120133 |
5 | 210223412000101 |
6 | 10120444034355 |
7 | 656561644136 |
oct | 144762403037 |
9 | 37874287638 |
10 | 13552453151 |
11 | 5825008706 |
12 | 27628329bb |
13 | 137c990963 |
14 | 927c9691d |
15 | 544bcba1b |
hex | 327ca061f |
13552453151 has 2 divisors, whose sum is σ = 13552453152. Its totient is φ = 13552453150.
The previous prime is 13552453111. The next prime is 13552453153. The reversal of 13552453151 is 15135425531.
13552453151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13552453151 - 214 = 13552436767 is a prime.
Together with 13552453153, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13552453153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6776226575 + 6776226576.
It is an arithmetic number, because the mean of its divisors is an integer number (6776226576).
Almost surely, 213552453151 is an apocalyptic number.
13552453151 is a deficient number, since it is larger than the sum of its proper divisors (1).
13552453151 is an equidigital number, since it uses as much as digits as its factorization.
13552453151 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 45000, while the sum is 35.
Adding to 13552453151 its reverse (15135425531), we get a palindrome (28687878682).
The spelling of 13552453151 in words is "thirteen billion, five hundred fifty-two million, four hundred fifty-three thousand, one hundred fifty-one".
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