Base | Representation |
---|---|
bin | 10011101110001011110… |
… | …110111011010111101111 |
3 | 11210120011110220201201221 |
4 | 103232023312323113233 |
5 | 134201033322131343 |
6 | 2514333125244211 |
7 | 166625430351250 |
oct | 23561366732757 |
9 | 4716143821657 |
10 | 1355261130223 |
11 | 482843638250 |
12 | 19a7aa263667 |
13 | 9aa53b34570 |
14 | 49848912b27 |
15 | 253c06035ed |
hex | 13b8bdbb5ef |
1355261130223 has 64 divisors (see below), whose sum is σ = 1839817728000. Its totient is φ = 964067184000.
The previous prime is 1355261130191. The next prime is 1355261130227. The reversal of 1355261130223 is 3220311625531.
It is not a de Polignac number, because 1355261130223 - 25 = 1355261130191 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1355261130227) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 34291528 + ... + 34331026.
It is an arithmetic number, because the mean of its divisors is an integer number (28747152000).
Almost surely, 21355261130223 is an apocalyptic number.
1355261130223 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1355261130223 is a deficient number, since it is larger than the sum of its proper divisors (484556597777).
1355261130223 is a wasteful number, since it uses less digits than its factorization.
1355261130223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39908.
The product of its (nonzero) digits is 32400, while the sum is 34.
Adding to 1355261130223 its reverse (3220311625531), we get a palindrome (4575572755754).
The spelling of 1355261130223 in words is "one trillion, three hundred fifty-five billion, two hundred sixty-one million, one hundred thirty thousand, two hundred twenty-three".
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