Base | Representation |
---|---|
bin | 11110110101011110100011… |
… | …001111100111111010010101 |
3 | 122210011210110021221000001102 |
4 | 132311132203033213322111 |
5 | 120233414221233344140 |
6 | 1200233141002035445 |
7 | 40364646052632011 |
oct | 3665364317477225 |
9 | 583153407830042 |
10 | 135616331153045 |
11 | 3a236621475286 |
12 | 1326342aaa8b85 |
13 | 5a89746847702 |
14 | 256bc18b1d541 |
15 | 10a2a5a742e15 |
hex | 7b57a33e7e95 |
135616331153045 has 8 divisors (see below), whose sum is σ = 163910385854880. Its totient is φ = 107712539274960.
The previous prime is 135616331153021. The next prime is 135616331153099. The reversal of 135616331153045 is 540351133616531.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 135616331153045 - 210 = 135616331152021 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 97565705171 + ... + 97565706560.
It is an arithmetic number, because the mean of its divisors is an integer number (20488798231860).
Almost surely, 2135616331153045 is an apocalyptic number.
It is an amenable number.
135616331153045 is a deficient number, since it is larger than the sum of its proper divisors (28294054701835).
135616331153045 is a wasteful number, since it uses less digits than its factorization.
135616331153045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 195131411875.
The product of its (nonzero) digits is 1458000, while the sum is 47.
Adding to 135616331153045 its reverse (540351133616531), we get a palindrome (675967464769576).
The spelling of 135616331153045 in words is "one hundred thirty-five trillion, six hundred sixteen billion, three hundred thirty-one million, one hundred fifty-three thousand, forty-five".
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