Base | Representation |
---|---|
bin | 11110111011101100001101… |
… | …011110001000100100001111 |
3 | 122211200121120112120002221201 |
4 | 132323230031132020210033 |
5 | 120312413202131312030 |
6 | 1201201234114010331 |
7 | 40440543112424014 |
oct | 3673541536104417 |
9 | 584617515502851 |
10 | 136043315104015 |
11 | 3a390711809400 |
12 | 13312132b769a7 |
13 | 5abaaa2737637 |
14 | 258476294770b |
15 | 10adbeb0a12ca |
hex | 7bbb0d78890f |
136043315104015 has 48 divisors (see below), whose sum is σ = 191842323027264. Its totient is φ = 92216474127360.
The previous prime is 136043315104007. The next prime is 136043315104027. The reversal of 136043315104015 is 510401513340631.
It is not a de Polignac number, because 136043315104015 - 23 = 136043315104007 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 63151092 + ... + 65269801.
It is an arithmetic number, because the mean of its divisors is an integer number (3996715063068).
Almost surely, 2136043315104015 is an apocalyptic number.
136043315104015 is a deficient number, since it is larger than the sum of its proper divisors (55799007923249).
136043315104015 is a wasteful number, since it uses less digits than its factorization.
136043315104015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 128421040 (or 128421029 counting only the distinct ones).
The product of its (nonzero) digits is 64800, while the sum is 37.
Adding to 136043315104015 its reverse (510401513340631), we get a palindrome (646444828444646).
The spelling of 136043315104015 in words is "one hundred thirty-six trillion, forty-three billion, three hundred fifteen million, one hundred four thousand, fifteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •