1361201740751 has 2 divisors, whose sum is σ = 1361201740752. Its totient is φ = 1361201740750.

The previous prime is 1361201740733. The next prime is 1361201740753. The reversal of 1361201740751 is 1570471021631.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1361201740751 - 2¹⁰ = 1361201739727 is a prime.

It is a super-2 number, since 2×1361201740751² (a number of 25 digits) contains 22 as substring.

Together with 1361201740753, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1361201740753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680600870375 + 680600870376.

It is an arithmetic number, because the mean of its divisors is an integer number (680600870376).

Almost surely, 2^{1361201740751} is an apocalyptic number.

1361201740751 is a deficient number, since it is larger than the sum of its proper divisors (1).

1361201740751 is an equidigital number, since it uses as much as digits as its factorization.

1361201740751 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 35280, while the sum is 38.

The spelling of 1361201740751 in words is "one trillion, three hundred sixty-one billion, two hundred one million, seven hundred forty thousand, seven hundred fifty-one".