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136134242653 is a prime number
BaseRepresentation
bin111111011001000111…
…0111011000101011101
3111000101102121001121011
41332302032323011131
54212300331231103
6142312245135221
712556350653503
oct1766216730535
9430342531534
10136134242653
115280925a462
12224730ba511
13cab6a13206
146836060673
15381b666d6d
hex1fb23bb15d

136134242653 has 2 divisors, whose sum is σ = 136134242654. Its totient is φ = 136134242652.

The previous prime is 136134242633. The next prime is 136134242663. The reversal of 136134242653 is 356242431631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 81957956089 + 54176286564 = 286283^2 + 232758^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-136134242653 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (136134242633) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68067121326 + 68067121327.

It is an arithmetic number, because the mean of its divisors is an integer number (68067121327).

Almost surely, 2136134242653 is an apocalyptic number.

It is an amenable number.

136134242653 is a deficient number, since it is larger than the sum of its proper divisors (1).

136134242653 is an equidigital number, since it uses as much as digits as its factorization.

136134242653 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 311040, while the sum is 40.

The spelling of 136134242653 in words is "one hundred thirty-six billion, one hundred thirty-four million, two hundred forty-two thousand, six hundred fifty-three".