Base | Representation |
---|---|
bin | 111111011001000111… |
… | …0111011000101100111 |
3 | 111000101102121001121112 |
4 | 1332302032323011213 |
5 | 4212300331231123 |
6 | 142312245135235 |
7 | 12556350653516 |
oct | 1766216730547 |
9 | 430342531545 |
10 | 136134242663 |
11 | 5280925a471 |
12 | 224730ba51b |
13 | cab6a13213 |
14 | 683606067d |
15 | 381b666d78 |
hex | 1fb23bb167 |
136134242663 has 2 divisors, whose sum is σ = 136134242664. Its totient is φ = 136134242662.
The previous prime is 136134242653. The next prime is 136134242669. The reversal of 136134242663 is 366242431631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 136134242663 - 214 = 136134226279 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 136134242663.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136134242669) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68067121331 + 68067121332.
It is an arithmetic number, because the mean of its divisors is an integer number (68067121332).
Almost surely, 2136134242663 is an apocalyptic number.
136134242663 is a deficient number, since it is larger than the sum of its proper divisors (1).
136134242663 is an equidigital number, since it uses as much as digits as its factorization.
136134242663 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 373248, while the sum is 41.
The spelling of 136134242663 in words is "one hundred thirty-six billion, one hundred thirty-four million, two hundred forty-two thousand, six hundred sixty-three".
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