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136228110335 = 5171602683651
BaseRepresentation
bin111111011011111010…
…0111111111111111111
3111000121222020000211222
41332313310333333333
54212443344012320
6142325441103555
712561600555302
oct1766764777777
9430558200758
10136228110335
1152857242659
122249a627bbb
13cb002ba715
1468446d6b39
153824a09825
hex1fb7d3ffff

136228110335 has 8 divisors (see below), whose sum is σ = 173089834416. Its totient is φ = 102571753600.

The previous prime is 136228110329. The next prime is 136228110349. The reversal of 136228110335 is 533011822631.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 136228110335 - 230 = 135154368511 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 136228110295 and 136228110304.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 801341741 + ... + 801341910.

It is an arithmetic number, because the mean of its divisors is an integer number (21636229302).

Almost surely, 2136228110335 is an apocalyptic number.

136228110335 is a deficient number, since it is larger than the sum of its proper divisors (36861724081).

136228110335 is a wasteful number, since it uses less digits than its factorization.

136228110335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1602683673.

The product of its (nonzero) digits is 25920, while the sum is 35.

Adding to 136228110335 its reverse (533011822631), we get a palindrome (669239932966).

The spelling of 136228110335 in words is "one hundred thirty-six billion, two hundred twenty-eight million, one hundred ten thousand, three hundred thirty-five".

Divisors: 1 5 17 85 1602683651 8013418255 27245622067 136228110335