Base | Representation |
---|---|
bin | 11001011010010110… |
… | …00110001100010011 |
3 | 1022012210022022110220 |
4 | 30231023012030103 |
5 | 210420023114210 |
6 | 10133432124123 |
7 | 662036523000 |
oct | 145513061423 |
9 | 38183268426 |
10 | 13642785555 |
11 | 5870aa6793 |
12 | 2788b36643 |
13 | 13955cac99 |
14 | 935c8c8a7 |
15 | 54cac1c70 |
hex | 32d2c6313 |
13642785555 has 128 divisors (see below), whose sum is σ = 27208704000. Its totient is φ = 5817474432.
The previous prime is 13642785493. The next prime is 13642785557. The reversal of 13642785555 is 55558724631.
It is not a de Polignac number, because 13642785555 - 216 = 13642720019 is a prime.
It is a super-2 number, since 2×136427855552 (a number of 21 digits) contains 22 as substring.
It is a hoax number, since the sum of its digits (51) coincides with the sum of the digits of its distinct prime factors.
It is a junction number, because it is equal to n+sod(n) for n = 13642785498 and 13642785507.
It is not an unprimeable number, because it can be changed into a prime (13642785557) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 6548544 + ... + 6550626.
It is an arithmetic number, because the mean of its divisors is an integer number (212568000).
Almost surely, 213642785555 is an apocalyptic number.
13642785555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13642785555 is a deficient number, since it is larger than the sum of its proper divisors (13565918445).
13642785555 is a wasteful number, since it uses less digits than its factorization.
13642785555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2198 (or 2184 counting only the distinct ones).
The product of its digits is 5040000, while the sum is 51.
The spelling of 13642785555 in words is "thirteen billion, six hundred forty-two million, seven hundred eighty-five thousand, five hundred fifty-five".
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