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13647966149 is a prime number
BaseRepresentation
bin11001011010111101…
…10110111111000101
31022020011001111220202
430231132312333011
5210422334404044
610134135140245
7662131540526
oct145536667705
938204044822
1013647966149
115873a14a74
12278a814685
1313966c301c
1493683a84d
1554d296c4e
hex32d7b6fc5

13647966149 has 2 divisors, whose sum is σ = 13647966150. Its totient is φ = 13647966148.

The previous prime is 13647966127. The next prime is 13647966151. The reversal of 13647966149 is 94166974631.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7347575524 + 6300390625 = 85718^2 + 79375^2 .

It is an emirp because it is prime and its reverse (94166974631) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13647966149 - 220 = 13646917573 is a prime.

Together with 13647966151, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13647966094 and 13647966103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13647966169) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6823983074 + 6823983075.

It is an arithmetic number, because the mean of its divisors is an integer number (6823983075).

Almost surely, 213647966149 is an apocalyptic number.

It is an amenable number.

13647966149 is a deficient number, since it is larger than the sum of its proper divisors (1).

13647966149 is an equidigital number, since it uses as much as digits as its factorization.

13647966149 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5878656, while the sum is 56.

The spelling of 13647966149 in words is "thirteen billion, six hundred forty-seven million, nine hundred sixty-six thousand, one hundred forty-nine".