1365130434165 has 32 divisors (see below), whose sum is σ = 2315328986880. Its totient is φ = 684460483584.

The previous prime is 1365130434113. The next prime is 1365130434281. The reversal of 1365130434165 is 5614340315631.

It is not a de Polignac number, because 1365130434165 - 2⁷ = 1365130434037 is a prime.

It is a super-2 number, since 2×1365130434165² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2828505 + ... + 3275774.

It is an arithmetic number, because the mean of its divisors is an integer number (72354030840).

Almost surely, 2^{1365130434165} is an apocalyptic number.

1365130434165 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

1365130434165 is a deficient number, since it is larger than the sum of its proper divisors (950198552715).

1365130434165 is a wasteful number, since it uses less digits than its factorization.

1365130434165 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6105181.

The product of its (nonzero) digits is 388800, while the sum is 42.

Adding to 1365130434165 its reverse (5614340315631), we get a palindrome (6979470749796).

The spelling of 1365130434165 in words is "one trillion, three hundred sixty-five billion, one hundred thirty million, four hundred thirty-four thousand, one hundred sixty-five".