Base | Representation |
---|---|
bin | 111111100101010011… |
… | …1011001111000100101 |
3 | 111001102221100000020020 |
4 | 1333022213121320211 |
5 | 4214120042012240 |
6 | 142421021025353 |
7 | 12602446004640 |
oct | 1771247317045 |
9 | 431387300206 |
10 | 136543313445 |
11 | 529a91603a0 |
12 | 225680b5259 |
13 | cb506ac436 |
14 | 6874506a57 |
15 | 384251d0d0 |
hex | 1fca9d9e25 |
136543313445 has 64 divisors (see below), whose sum is σ = 272433936384. Its totient is φ = 56733477120.
The previous prime is 136543313443. The next prime is 136543313461. The reversal of 136543313445 is 544313345631.
It is not a de Polignac number, because 136543313445 - 21 = 136543313443 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 136543313397 and 136543313406.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (136543313443) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 7571259 + ... + 7589271.
It is an arithmetic number, because the mean of its divisors is an integer number (4256780256).
Almost surely, 2136543313445 is an apocalyptic number.
136543313445 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
136543313445 is a deficient number, since it is larger than the sum of its proper divisors (135890622939).
136543313445 is a wasteful number, since it uses less digits than its factorization.
136543313445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24602.
The product of its digits is 777600, while the sum is 42.
The spelling of 136543313445 in words is "one hundred thirty-six billion, five hundred forty-three million, three hundred thirteen thousand, four hundred forty-five".
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