Base | Representation |
---|---|
bin | 111111100111001000… |
… | …1000010101101111111 |
3 | 111001121012120200001121 |
4 | 1333032101002231333 |
5 | 4214231231412010 |
6 | 142431045451411 |
7 | 12604121414032 |
oct | 1771621025577 |
9 | 431535520047 |
10 | 136604560255 |
11 | 52a2a792a99 |
12 | 22584710b67 |
13 | cb602a4a57 |
14 | 687c6cb019 |
15 | 3847aba3da |
hex | 1fce442b7f |
136604560255 has 4 divisors (see below), whose sum is σ = 163925472312. Its totient is φ = 109283648200.
The previous prime is 136604560237. The next prime is 136604560283. The reversal of 136604560255 is 552065406631.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 552065406631 = 53 ⋅10416328427.
It is not a de Polignac number, because 136604560255 - 29 = 136604559743 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13660456021 + ... + 13660456030.
It is an arithmetic number, because the mean of its divisors is an integer number (40981368078).
Almost surely, 2136604560255 is an apocalyptic number.
136604560255 is a deficient number, since it is larger than the sum of its proper divisors (27320912057).
136604560255 is an equidigital number, since it uses as much as digits as its factorization.
136604560255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27320912056.
The product of its (nonzero) digits is 648000, while the sum is 43.
Adding to 136604560255 its reverse (552065406631), we get a palindrome (688669966886).
The spelling of 136604560255 in words is "one hundred thirty-six billion, six hundred four million, five hundred sixty thousand, two hundred fifty-five".
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