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1366471225487 is a prime number
BaseRepresentation
bin10011111000101000000…
…010000011000010001111
311211122002201200120111102
4103320220002003002033
5134342013113203422
62523425340413315
7200503300525604
oct23705002030217
94748081616442
101366471225487
11487576423795
121a09b854723b
139bb1c43c224
144a1cd6726ab
1525829843192
hex13e2808308f

1366471225487 has 2 divisors, whose sum is σ = 1366471225488. Its totient is φ = 1366471225486.

The previous prime is 1366471225397. The next prime is 1366471225489. The reversal of 1366471225487 is 7845221746631.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (7845221746631) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1366471225487 - 212 = 1366471221391 is a prime.

It is a super-2 number, since 2×13664712254872 (a number of 25 digits) contains 22 as substring.

Together with 1366471225489, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1366471225489) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 683235612743 + 683235612744.

It is an arithmetic number, because the mean of its divisors is an integer number (683235612744).

Almost surely, 21366471225487 is an apocalyptic number.

1366471225487 is a deficient number, since it is larger than the sum of its proper divisors (1).

1366471225487 is an equidigital number, since it uses as much as digits as its factorization.

1366471225487 is an evil number, because the sum of its binary digits is even.

The product of its digits is 13547520, while the sum is 56.

The spelling of 1366471225487 in words is "one trillion, three hundred sixty-six billion, four hundred seventy-one million, two hundred twenty-five thousand, four hundred eighty-seven".