Base | Representation |
---|---|
bin | 10011111010010001001… |
… | …111011011000000110010 |
3 | 11211210122202001122101020 |
4 | 103322101033123000302 |
5 | 134404122000324000 |
6 | 2524320433120310 |
7 | 200565112664064 |
oct | 23722117330062 |
9 | 4753582048336 |
10 | 1368236339250 |
11 | 4882a181a8a0 |
12 | 1a120b6b9096 |
13 | 9c041036241 |
14 | 4a319c67734 |
15 | 258ce7a9ba0 |
hex | 13e913db032 |
1368236339250 has 128 divisors (see below), whose sum is σ = 3812225624064. Its totient is φ = 323979768000.
The previous prime is 1368236339237. The next prime is 1368236339251. The reversal of 1368236339250 is 529336328631.
It is a junction number, because it is equal to n+sod(n) for n = 1368236339193 and 1368236339202.
It is not an unprimeable number, because it can be changed into a prime (1368236339251) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1573702 + ... + 2283201.
It is an arithmetic number, because the mean of its divisors is an integer number (29783012688).
Almost surely, 21368236339250 is an apocalyptic number.
1368236339250 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1368236339250 is an abundant number, since it is smaller than the sum of its proper divisors (2443989284814).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1368236339250 is a wasteful number, since it uses less digits than its factorization.
1368236339250 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3856977 (or 3856967 counting only the distinct ones).
The product of its (nonzero) digits is 4199040, while the sum is 51.
The spelling of 1368236339250 in words is "one trillion, three hundred sixty-eight billion, two hundred thirty-six million, three hundred thirty-nine thousand, two hundred fifty".
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