Base | Representation |
---|---|
bin | 1100100001010100101110… |
… | …1100111011000110000000 |
3 | 1210202002002211101110001122 |
4 | 3020111023230323012000 |
5 | 3301023034401020024 |
6 | 45140150205451412 |
7 | 2620415115252635 |
oct | 310251354730600 |
9 | 53662084343048 |
10 | 13766640251264 |
11 | 442844358750a |
12 | 1664097b70b68 |
13 | 78b25b49aba4 |
14 | 358447a5218c |
15 | 18d17dde8d5e |
hex | c854bb3b180 |
13766640251264 has 32 divisors (see below), whose sum is σ = 28063536279240. Its totient is φ = 6723242910720.
The previous prime is 13766640251227. The next prime is 13766640251269. The reversal of 13766640251264 is 46215204666731.
It is a tau number, because it is divible by the number of its divisors (32).
It is a super-3 number, since 3×137666402512643 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13766640251269) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1250597717 + ... + 1250608724.
Almost surely, 213766640251264 is an apocalyptic number.
It is an amenable number.
13766640251264 is an abundant number, since it is smaller than the sum of its proper divisors (14296896027976).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13766640251264 is an equidigital number, since it uses as much as digits as its factorization.
13766640251264 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2501206498 (or 2501206486 counting only the distinct ones).
The product of its (nonzero) digits is 8709120, while the sum is 53.
The spelling of 13766640251264 in words is "thirteen trillion, seven hundred sixty-six billion, six hundred forty million, two hundred fifty-one thousand, two hundred sixty-four".
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