13961251453 has 2 divisors, whose sum is σ = 13961251454. Its totient is φ = 13961251452.

The previous prime is 13961251439. The next prime is 13961251457. The reversal of 13961251453 is 35415216931.

It is a happy number.

13961251453 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13744514169 + 216737284 = 117237^2 + 14722^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13961251453 is a prime.

It is a super-2 number, since 2×13961251453² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13961251457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6980625726 + 6980625727.

It is an arithmetic number, because the mean of its divisors is an integer number (6980625727).

Almost surely, 2^13961251453 is an apocalyptic number.

It is an amenable number.

13961251453 is a deficient number, since it is larger than the sum of its proper divisors (1).

13961251453 is an equidigital number, since it uses as much as digits as its factorization.

13961251453 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 97200, while the sum is 40.

The spelling of 13961251453 in words is "thirteen billion, nine hundred sixty-one million, two hundred fifty-one thousand, four hundred fifty-three".