140013020110013 has 4 divisors (see below), whose sum is σ = 143797155788700. Its totient is φ = 136228884431328.

The previous prime is 140013020110009. The next prime is 140013020110021. The reversal of 140013020110013 is 310011020310041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 52734581612164 + 87278438497849 = 7261858^2 + 9342293^2 .

It is a cyclic number.

It is not a de Polignac number, because 140013020110013 - 2² = 140013020110009 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140013020109973 and 140013020110000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140013020119013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1892067839288 + ... + 1892067839361.

It is an arithmetic number, because the mean of its divisors is an integer number (35949288947175).

Almost surely, 2^{140013020110013} is an apocalyptic number.

It is an amenable number.

140013020110013 is a deficient number, since it is larger than the sum of its proper divisors (3784135678687).

140013020110013 is an equidigital number, since it uses as much as digits as its factorization.

140013020110013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3784135678686.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 140013020110013 its reverse (310011020310041), we get a palindrome (450024040420054).

The spelling of 140013020110013 in words is "one hundred forty trillion, thirteen billion, twenty million, one hundred ten thousand, thirteen".