14004013223111 has 8 divisors (see below), whose sum is σ = 14481198695664. Its totient is φ = 13534715113920.

The previous prime is 14004013223107. The next prime is 14004013223201. The reversal of 14004013223111 is 11132231040041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14004013223111 - 2² = 14004013223107 is a prime.

It is a super-2 number, since 2×14004013223111² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14004013223911) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1971837230 + ... + 1971844331.

It is an arithmetic number, because the mean of its divisors is an integer number (1810149836958).

Almost surely, 2^{14004013223111} is an apocalyptic number.

14004013223111 is a deficient number, since it is larger than the sum of its proper divisors (477185472553).

14004013223111 is an equidigital number, since it uses as much as digits as its factorization.

14004013223111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3943681681.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 14004013223111 its reverse (11132231040041), we get a palindrome (25136244263152).

The spelling of 14004013223111 in words is "fourteen trillion, four billion, thirteen million, two hundred twenty-three thousand, one hundred eleven".