1400430130133 has 6 divisors (see below), whose sum is σ = 1487654152386. Its totient is φ = 1318051886912.

The previous prime is 1400430130129. The next prime is 1400430130139. The reversal of 1400430130133 is 3310310340041.

It can be written as a sum of positive squares in 3 ways, for example, as 296129695684 + 1104300434449 = 544178^2 + 1050857^2 .

It is not a de Polignac number, because 1400430130133 - 2² = 1400430130129 is a prime.

It is a super-2 number, since 2×1400430130133² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1400430130099 and 1400430130108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1400430130139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 2422889210 + ... + 2422889787.

It is an arithmetic number, because the mean of its divisors is an integer number (247942358731).

Almost surely, 2^{1400430130133} is an apocalyptic number.

It is an amenable number.

1400430130133 is a deficient number, since it is larger than the sum of its proper divisors (87224022253).

1400430130133 is an equidigital number, since it uses as much as digits as its factorization.

1400430130133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4845779031 (or 4845779014 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 1400430130133 its reverse (3310310340041), we get a palindrome (4710740470174).

The spelling of 1400430130133 in words is "one trillion, four hundred billion, four hundred thirty million, one hundred thirty thousand, one hundred thirty-three".