Base | Representation |
---|---|
bin | 10100011000010000110… |
… | …000001111101011110111 |
3 | 11221212210002201111122212 |
4 | 110120100300033223313 |
5 | 140421100221433421 |
6 | 2551204202244035 |
7 | 203115135112424 |
oct | 24302060175367 |
9 | 4855702644585 |
10 | 1400440421111 |
11 | 49aa18121186 |
12 | 1a74b87b661b |
13 | a20a3c2b894 |
14 | 4bad2cd2d4b |
15 | 26666b59e5b |
hex | 14610c0faf7 |
1400440421111 has 2 divisors, whose sum is σ = 1400440421112. Its totient is φ = 1400440421110.
The previous prime is 1400440421101. The next prime is 1400440421123. The reversal of 1400440421111 is 1111240440041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1400440421111 - 26 = 1400440421047 is a prime.
It is a super-2 number, since 2×14004404211112 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1400440421101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700220210555 + 700220210556.
It is an arithmetic number, because the mean of its divisors is an integer number (700220210556).
Almost surely, 21400440421111 is an apocalyptic number.
1400440421111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1400440421111 is an equidigital number, since it uses as much as digits as its factorization.
1400440421111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 512, while the sum is 23.
Adding to 1400440421111 its reverse (1111240440041), we get a palindrome (2511680861152).
The spelling of 1400440421111 in words is "one trillion, four hundred billion, four hundred forty million, four hundred twenty-one thousand, one hundred eleven".
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