1400444125301 has 6 divisors (see below), whose sum is σ = 1516457248290. Its totient is φ = 1292717653968.

The previous prime is 1400444125291. The next prime is 1400444125303. The reversal of 1400444125301 is 1035214440041.

It can be written as a sum of positive squares in 3 ways, for example, as 34815828100 + 1365628297201 = 186590^2 + 1168601^2 .

It is a de Polignac number, because none of the positive numbers 2^k-1400444125301 is a prime.

It is a super-2 number, since 2×1400444125301² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1400444125303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 4143325646 + ... + 4143325983.

It is an arithmetic number, because the mean of its divisors is an integer number (252742874715).

Almost surely, 2^{1400444125301} is an apocalyptic number.

It is an amenable number.

1400444125301 is a deficient number, since it is larger than the sum of its proper divisors (116013122989).

1400444125301 is an equidigital number, since it uses as much as digits as its factorization.

1400444125301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8286651655 (or 8286651642 counting only the distinct ones).

The product of its (nonzero) digits is 7680, while the sum is 29.

Adding to 1400444125301 its reverse (1035214440041), we get a palindrome (2435658565342).

The spelling of 1400444125301 in words is "one trillion, four hundred billion, four hundred forty-four million, one hundred twenty-five thousand, three hundred one".