1401000011111 has 4 divisors (see below), whose sum is σ = 1401434972424. Its totient is φ = 1400565049800.

The previous prime is 1401000011107. The next prime is 1401000011207. The reversal of 1401000011111 is 1111100001041.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1401000011111 - 2² = 1401000011107 is a prime.

It is a super-2 number, since 2×1401000011111² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1401000011092 and 1401000011101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1401000011611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 217475825 + ... + 217482266.

It is an arithmetic number, because the mean of its divisors is an integer number (350358743106).

Almost surely, 2^{1401000011111} is an apocalyptic number.

1401000011111 is a deficient number, since it is larger than the sum of its proper divisors (434961313).

1401000011111 is an equidigital number, since it uses as much as digits as its factorization.

1401000011111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 434961312.

The product of its (nonzero) digits is 4, while the sum is 11.

Adding to 1401000011111 its reverse (1111100001041), we get a palindrome (2512100012152).

The spelling of 1401000011111 in words is "one trillion, four hundred one billion, eleven thousand, one hundred eleven".