Base | Representation |
---|---|
bin | 11111110110111000100100… |
… | …011000011001011010101111 |
3 | 200101002111001211101000221002 |
4 | 133312320210120121122233 |
5 | 121331034344034133310 |
6 | 1213554041544230515 |
7 | 41340455011356005 |
oct | 3766704430313257 |
9 | 611074054330832 |
10 | 140111033505455 |
11 | 407098347aa2a1 |
12 | 1386a55976b43b |
13 | 602454c07919c |
14 | 26855a5860a75 |
15 | 112e9221d2da5 |
hex | 7f6e246196af |
140111033505455 has 64 divisors (see below), whose sum is σ = 176419227156480. Its totient is φ = 106737615129600.
The previous prime is 140111033505433. The next prime is 140111033505467. The reversal of 140111033505455 is 554505330111041.
It is not a de Polignac number, because 140111033505455 - 28 = 140111033505199 is a prime.
It is a super-2 number, since 2×1401110335054552 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2816786885 + ... + 2816836625.
It is an arithmetic number, because the mean of its divisors is an integer number (2756550424320).
Almost surely, 2140111033505455 is an apocalyptic number.
140111033505455 is a deficient number, since it is larger than the sum of its proper divisors (36308193651025).
140111033505455 is a wasteful number, since it uses less digits than its factorization.
140111033505455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 52080.
The product of its (nonzero) digits is 90000, while the sum is 38.
Adding to 140111033505455 its reverse (554505330111041), we get a palindrome (694616363616496).
The spelling of 140111033505455 in words is "one hundred forty trillion, one hundred eleven billion, thirty-three million, five hundred five thousand, four hundred fifty-five".
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