1401110420111 has 2 divisors, whose sum is σ = 1401110420112. Its totient is φ = 1401110420110.

The previous prime is 1401110420089. The next prime is 1401110420113. The reversal of 1401110420111 is 1110240111041.

It is a strong prime.

It is an emirp because it is prime and its reverse (1110240111041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1401110420111 - 2³⁴ = 1383930550927 is a prime.

It is a super-2 number, since 2×1401110420111² (a number of 25 digits) contains 22 as substring.

Together with 1401110420113, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1401110420111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1401110420113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700555210055 + 700555210056.

It is an arithmetic number, because the mean of its divisors is an integer number (700555210056).

Almost surely, 2^{1401110420111} is an apocalyptic number.

1401110420111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1401110420111 is an equidigital number, since it uses as much as digits as its factorization.

1401110420111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32, while the sum is 17.

Adding to 1401110420111 its reverse (1110240111041), we get a palindrome (2511350531152).

The spelling of 1401110420111 in words is "one trillion, four hundred one billion, one hundred ten million, four hundred twenty thousand, one hundred eleven".