140113151 has 2 divisors, whose sum is σ = 140113152. Its totient is φ = 140113150.

The previous prime is 140113139. The next prime is 140113153. The reversal of 140113151 is 151311041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 140113151 - 2¹⁰ = 140112127 is a prime.

Together with 140113153, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140113153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70056575 + 70056576.

It is an arithmetic number, because the mean of its divisors is an integer number (70056576).

Almost surely, 2^140113151 is an apocalyptic number.

140113151 is a deficient number, since it is larger than the sum of its proper divisors (1).

140113151 is an equidigital number, since it uses as much as digits as its factorization.

140113151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60, while the sum is 17.

The square root of 140113151 is about 11836.9401029151. The cubic root of 140113151 is about 519.3892620148.

Adding to 140113151 its reverse (151311041), we get a palindrome (291424192).

The spelling of 140113151 in words is "one hundred forty million, one hundred thirteen thousand, one hundred fifty-one".