Search a number
-
+
14011343207 is a prime number
BaseRepresentation
bin11010000110010010…
…00010000101100111
31100011110210222112022
431003021002011213
5212143400440312
610234155413355
71004133311051
oct150311020547
940143728468
1014011343207
115a40046594
12287045425b
131423a80c34
1496cbca8d1
15570124172
hex343242167

14011343207 has 2 divisors, whose sum is σ = 14011343208. Its totient is φ = 14011343206.

The previous prime is 14011343173. The next prime is 14011343209. The reversal of 14011343207 is 70234311041.

It is a strong prime.

It is an emirp because it is prime and its reverse (70234311041) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14011343207 is a prime.

Together with 14011343209, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14011343209) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005671603 + 7005671604.

It is an arithmetic number, because the mean of its divisors is an integer number (7005671604).

Almost surely, 214011343207 is an apocalyptic number.

14011343207 is a deficient number, since it is larger than the sum of its proper divisors (1).

14011343207 is an equidigital number, since it uses as much as digits as its factorization.

14011343207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 26.

Adding to 14011343207 its reverse (70234311041), we get a palindrome (84245654248).

The spelling of 14011343207 in words is "fourteen billion, eleven million, three hundred forty-three thousand, two hundred seven".