Base | Representation |
---|---|
bin | 10100011000111010011… |
… | …110100010001010111111 |
3 | 11221221120212220012102012 |
4 | 110120322132202022333 |
5 | 140424013421440221 |
6 | 2551401445521435 |
7 | 203141365034351 |
oct | 24307236421277 |
9 | 4857525805365 |
10 | 1401140421311 |
11 | 4a0247270744 |
12 | 1a767311327b |
13 | a2185c6b097 |
14 | 4bb5bc6b0d1 |
15 | 266a832c65b |
hex | 1463a7a22bf |
1401140421311 has 4 divisors (see below), whose sum is σ = 1483560446112. Its totient is φ = 1318720396512.
The previous prime is 1401140421271. The next prime is 1401140421337. The reversal of 1401140421311 is 1131240411041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1401140421311 - 210 = 1401140420287 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1401140421371) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41210012375 + ... + 41210012408.
It is an arithmetic number, because the mean of its divisors is an integer number (370890111528).
Almost surely, 21401140421311 is an apocalyptic number.
1401140421311 is a deficient number, since it is larger than the sum of its proper divisors (82420024801).
1401140421311 is an equidigital number, since it uses as much as digits as its factorization.
1401140421311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 82420024800.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 1401140421311 its reverse (1131240411041), we get a palindrome (2532380832352).
The spelling of 1401140421311 in words is "one trillion, four hundred one billion, one hundred forty million, four hundred twenty-one thousand, three hundred eleven".
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