Base | Representation |
---|---|
bin | 11111110111000011101101… |
… | …110101111101111110110000 |
3 | 200101010121222000212022100221 |
4 | 133313003231311331332300 |
5 | 121331233402333144100 |
6 | 1214003341421022424 |
7 | 41341360436035621 |
oct | 3767035565757660 |
9 | 611117860768327 |
10 | 140123003412400 |
11 | 40713917477578 |
12 | 1387093a3b4a14 |
13 | 6025708c05568 |
14 | 2685dbd487a48 |
15 | 112edc2eac01a |
hex | 7f70edd7dfb0 |
140123003412400 has 30 divisors (see below), whose sum is σ = 336645515699252. Its totient is φ = 56049201364800.
The previous prime is 140123003412383. The next prime is 140123003412419. The reversal of 140123003412400 is 4214300321041.
It is a super-2 number, since 2×1401230034124002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 175153753866 + ... + 175153754665.
Almost surely, 2140123003412400 is an apocalyptic number.
140123003412400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
140123003412400 is an abundant number, since it is smaller than the sum of its proper divisors (196522512286852).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
140123003412400 is a wasteful number, since it uses less digits than its factorization.
140123003412400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 350307508549 (or 350307508538 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 140123003412400 its reverse (4214300321041), we get a palindrome (144337303733441).
The spelling of 140123003412400 in words is "one hundred forty trillion, one hundred twenty-three billion, three million, four hundred twelve thousand, four hundred".
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