1401230113232 has 40 divisors (see below), whose sum is σ = 2857868974560. Its totient is φ = 663718043520.

The previous prime is 1401230113193. The next prime is 1401230113237. The reversal of 1401230113232 is 2323110321041.

It is a junction number, because it is equal to n+sod(n) for n = 1401230113198 and 1401230113207.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1401230113237) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11901083 + ... + 12018245.

It is an arithmetic number, because the mean of its divisors is an integer number (71446724364).

Almost surely, 2^{1401230113232} is an apocalyptic number.

It is an amenable number.

1401230113232 is an abundant number, since it is smaller than the sum of its proper divisors (1456638861328).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1401230113232 is a wasteful number, since it uses less digits than its factorization.

1401230113232 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 156531 (or 156525 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 1401230113232 its reverse (2323110321041), we get a palindrome (3724340434273).

The spelling of 1401230113232 in words is "one trillion, four hundred one billion, two hundred thirty million, one hundred thirteen thousand, two hundred thirty-two".