140142113 has 2 divisors, whose sum is σ = 140142114. Its totient is φ = 140142112.

The previous prime is 140142083. The next prime is 140142127. The reversal of 140142113 is 311241041.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129436129 + 10705984 = 11377^2 + 3272^2 .

It is an emirp because it is prime and its reverse (311241041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140142113 - 2⁶ = 140142049 is a prime.

It is a super-2 number, since 2×140142113² = 39279623672209538, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 140142091 and 140142100.

It is not a weakly prime, because it can be changed into another prime (140142133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70071056 + 70071057.

It is an arithmetic number, because the mean of its divisors is an integer number (70071057).

Almost surely, 2^140142113 is an apocalyptic number.

It is an amenable number.

140142113 is a deficient number, since it is larger than the sum of its proper divisors (1).

140142113 is an equidigital number, since it uses as much as digits as its factorization.

140142113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 140142113 is about 11838.1634133002. The cubic root of 140142113 is about 519.4250462253.

Adding to 140142113 its reverse (311241041), we get a palindrome (451383154).

The spelling of 140142113 in words is "one hundred forty million, one hundred forty-two thousand, one hundred thirteen".