140151241301 has 2 divisors, whose sum is σ = 140151241302. Its totient is φ = 140151241300.

The previous prime is 140151241297. The next prime is 140151241303. The reversal of 140151241301 is 103142151041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108725170225 + 31426071076 = 329735^2 + 177274^2 .

It is an emirp because it is prime and its reverse (103142151041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140151241301 - 2² = 140151241297 is a prime.

It is a super-2 number, since 2×140151241301² (a number of 23 digits) contains 22 as substring.

Together with 140151241303, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140151241303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70075620650 + 70075620651.

It is an arithmetic number, because the mean of its divisors is an integer number (70075620651).

Almost surely, 2^140151241301 is an apocalyptic number.

It is an amenable number.

140151241301 is a deficient number, since it is larger than the sum of its proper divisors (1).

140151241301 is an equidigital number, since it uses as much as digits as its factorization.

140151241301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 480, while the sum is 23.

Adding to 140151241301 its reverse (103142151041), we get a palindrome (243293392342).

The spelling of 140151241301 in words is "one hundred forty billion, one hundred fifty-one million, two hundred forty-one thousand, three hundred one".