1402032433113 has 48 divisors (see below), whose sum is σ = 2208135121920. Its totient is φ = 852095462400.

The previous prime is 1402032433051. The next prime is 1402032433127. The reversal of 1402032433113 is 3113342302041.

It is a happy number.

1402032433113 is a `hidden beast` number, since 1 + 4 + 0 + 2 + 0 + 324 + 331 + 1 + 3 = 666.

It is not a de Polignac number, because 1402032433113 - 2³⁰ = 1400958691289 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1402032433133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2880553 + ... + 3331913.

It is an arithmetic number, because the mean of its divisors is an integer number (46002815040).

Almost surely, 2^{1402032433113} is an apocalyptic number.

1402032433113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1402032433113 is a deficient number, since it is larger than the sum of its proper divisors (806102688807).

1402032433113 is a wasteful number, since it uses less digits than its factorization.

1402032433113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 451710 (or 451707 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 1402032433113 its reverse (3113342302041), we get a palindrome (4515374735154).

The spelling of 1402032433113 in words is "one trillion, four hundred two billion, thirty-two million, four hundred thirty-three thousand, one hundred thirteen".