140214142133310 has 256 divisors, whose sum is σ = 411334026854400. Its totient is φ = 29898140428800.

The previous prime is 140214142133269. The next prime is 140214142133311. The reversal of 140214142133310 is 13331241412041.

It is a super-2 number, since 2×140214142133310² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140214142133311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 118537981 + ... + 119714999.

It is an arithmetic number, because the mean of its divisors is an integer number (1606773542400).

Almost surely, 2^{140214142133310} is an apocalyptic number.

140214142133310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 140214142133310, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (205667013427200).

140214142133310 is an abundant number, since it is smaller than the sum of its proper divisors (271119884721090).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

140214142133310 is a wasteful number, since it uses less digits than its factorization.

140214142133310 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1177727.

The product of its (nonzero) digits is 6912, while the sum is 30.

Adding to 140214142133310 its reverse (13331241412041), we get a palindrome (153545383545351).

The spelling of 140214142133310 in words is "one hundred forty trillion, two hundred fourteen billion, one hundred forty-two million, one hundred thirty-three thousand, three hundred ten".