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14022013055 = 52804402611
BaseRepresentation
bin11010000111100011…
…01111000001111111
31100012012220001210212
431003301233001333
5212204113404210
610235220223035
71004323100351
oct150361570177
940165801725
1014022013055
115a46073a46
122873b3aa7b
13142604865b
149703a70d1
15571030805
hex343c6f07f

14022013055 has 4 divisors (see below), whose sum is σ = 16826415672. Its totient is φ = 11217610440.

The previous prime is 14022013051. The next prime is 14022013067. The reversal of 14022013055 is 55031022041.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 14022013055 - 22 = 14022013051 is a prime.

It is a super-2 number, since 2×140220130552 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14022013055.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14022013051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1402201301 + ... + 1402201310.

It is an arithmetic number, because the mean of its divisors is an integer number (4206603918).

Almost surely, 214022013055 is an apocalyptic number.

14022013055 is a deficient number, since it is larger than the sum of its proper divisors (2804402617).

14022013055 is an equidigital number, since it uses as much as digits as its factorization.

14022013055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2804402616.

The product of its (nonzero) digits is 1200, while the sum is 23.

Adding to 14022013055 its reverse (55031022041), we get a palindrome (69053035096).

The spelling of 14022013055 in words is "fourteen billion, twenty-two million, thirteen thousand, fifty-five".

Divisors: 1 5 2804402611 14022013055