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1402311001031 is a prime number
BaseRepresentation
bin10100011010000000001…
…111111100001111000111
311222001121110112210220122
4110122000033330033013
5140433413104013111
62552113543252155
7203212400560253
oct24320017741707
94861543483818
101402311001031
114a07980025a6
121a793b14a05b
13a23116313c5
144bc2d4dd263
1526725ea5cdb
hex146803fc3c7

1402311001031 has 2 divisors, whose sum is σ = 1402311001032. Its totient is φ = 1402311001030.

The previous prime is 1402311001009. The next prime is 1402311001043. The reversal of 1402311001031 is 1301001132041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1402311001031 - 26 = 1402311000967 is a prime.

It is a super-3 number, since 3×14023110010313 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1402311001061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701155500515 + 701155500516.

It is an arithmetic number, because the mean of its divisors is an integer number (701155500516).

Almost surely, 21402311001031 is an apocalyptic number.

1402311001031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1402311001031 is an equidigital number, since it uses as much as digits as its factorization.

1402311001031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1402311001031 its reverse (1301001132041), we get a palindrome (2703312133072).

The spelling of 1402311001031 in words is "one trillion, four hundred two billion, three hundred eleven million, one thousand, thirty-one".