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14023323243455 = 52804664648691
BaseRepresentation
bin1100110000010000111100…
…1100110101001110111111
31211122121122111201111000012
43030010033030311032333
53314224231222242310
645454120433053435
72645103010554641
oct314041714651677
954577574644005
1014023323243455
1145172924246a9
1216a59926b727b
137a9516c8b716
14366a37c60891
15194ba37adc05
hexcc10f3353bf

14023323243455 has 4 divisors (see below), whose sum is σ = 16827987892152. Its totient is φ = 11218658594760.

The previous prime is 14023323243421. The next prime is 14023323243473. The reversal of 14023323243455 is 55434232332041.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 14023323243455 - 220 = 14023322194879 is a prime.

It is a super-2 number, since 2×140233232434552 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1402332324341 + ... + 1402332324350.

It is an arithmetic number, because the mean of its divisors is an integer number (4206996973038).

Almost surely, 214023323243455 is an apocalyptic number.

14023323243455 is a deficient number, since it is larger than the sum of its proper divisors (2804664648697).

14023323243455 is an equidigital number, since it uses as much as digits as its factorization.

14023323243455 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2804664648696.

The product of its (nonzero) digits is 1036800, while the sum is 41.

Adding to 14023323243455 its reverse (55434232332041), we get a palindrome (69457555575496).

The spelling of 14023323243455 in words is "fourteen trillion, twenty-three billion, three hundred twenty-three million, two hundred forty-three thousand, four hundred fifty-five".

Divisors: 1 5 2804664648691 14023323243455