Base | Representation |
---|---|
bin | 11010001000101011… |
… | …01101010110000111 |
3 | 1100012212122011201111 |
4 | 31010111231112013 |
5 | 212214022141320 |
6 | 10240154305451 |
7 | 1004466205030 |
oct | 150425552607 |
9 | 40185564644 |
10 | 14031443335 |
11 | 5a50425068 |
12 | 2877128287 |
13 | 1427c9aac0 |
14 | 97173da87 |
15 | 571c94a5a |
hex | 34456d587 |
14031443335 has 32 divisors (see below), whose sum is σ = 20937071232. Its totient is φ = 8789852160.
The previous prime is 14031443333. The next prime is 14031443339. The reversal of 14031443335 is 53334413041.
14031443335 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 14031443335 - 21 = 14031443333 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14031443297 and 14031443306.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14031443333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 114826 + ... + 203095.
It is an arithmetic number, because the mean of its divisors is an integer number (654283476).
Almost surely, 214031443335 is an apocalyptic number.
14031443335 is a deficient number, since it is larger than the sum of its proper divisors (6905627897).
14031443335 is a wasteful number, since it uses less digits than its factorization.
14031443335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 318043.
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 14031443335 its reverse (53334413041), we get a palindrome (67365856376).
The spelling of 14031443335 in words is "fourteen billion, thirty-one million, four hundred forty-three thousand, three hundred thirty-five".
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