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14032523023103 = 131079424847931
BaseRepresentation
bin1100110000110011001110…
…0011001101001011111111
31211200111101122201201011202
43030030303203031023333
53314402101343214403
645502241352210115
72645550000444644
oct314146343151377
954614348651152
1014032523023103
114520183468282
1216a771b69993b
137aa351c49910
1436726b9dbdcb
1519504129e688
hexcc3338cd2ff

14032523023103 has 4 divisors (see below), whose sum is σ = 15111947871048. Its totient is φ = 12953098175160.

The previous prime is 14032523023021. The next prime is 14032523023117. The reversal of 14032523023103 is 30132032523041.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-14032523023103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14032523043103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 539712423953 + ... + 539712423978.

It is an arithmetic number, because the mean of its divisors is an integer number (3777986967762).

Almost surely, 214032523023103 is an apocalyptic number.

14032523023103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

14032523023103 is a deficient number, since it is larger than the sum of its proper divisors (1079424847945).

14032523023103 is a wasteful number, since it uses less digits than its factorization.

14032523023103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1079424847944.

The product of its (nonzero) digits is 12960, while the sum is 29.

Adding to 14032523023103 its reverse (30132032523041), we get a palindrome (44164555546144).

The spelling of 14032523023103 in words is "fourteen trillion, thirty-two billion, five hundred twenty-three million, twenty-three thousand, one hundred three".

Divisors: 1 13 1079424847931 14032523023103