14033122000421 has 4 divisors (see below), whose sum is σ = 14033886058752. Its totient is φ = 14032357942092.

The previous prime is 14033122000411. The next prime is 14033122000481. The reversal of 14033122000421 is 12400022133041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14033122000421 - 2¹⁰ = 14033121999397 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14033122000411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 382001615 + ... + 382038348.

It is an arithmetic number, because the mean of its divisors is an integer number (3508471514688).

Almost surely, 2^{14033122000421} is an apocalyptic number.

It is an amenable number.

14033122000421 is a deficient number, since it is larger than the sum of its proper divisors (764058331).

14033122000421 is an equidigital number, since it uses as much as digits as its factorization.

14033122000421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 764058330.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 14033122000421 its reverse (12400022133041), we get a palindrome (26433144133462).

The spelling of 14033122000421 in words is "fourteen trillion, thirty-three billion, one hundred twenty-two million, four hundred twenty-one", and thus it is an aban number.