14040050251111 has 2 divisors, whose sum is σ = 14040050251112. Its totient is φ = 14040050251110.

The previous prime is 14040050251037. The next prime is 14040050251223. The reversal of 14040050251111 is 11115205004041.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14040050251111 - 2¹¹ = 14040050249063 is a prime.

It is a super-2 number, since 2×14040050251111² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14040050221111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7020025125555 + 7020025125556.

It is an arithmetic number, because the mean of its divisors is an integer number (7020025125556).

Almost surely, 2^{14040050251111} is an apocalyptic number.

14040050251111 is a deficient number, since it is larger than the sum of its proper divisors (1).

14040050251111 is an equidigital number, since it uses as much as digits as its factorization.

14040050251111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 800, while the sum is 25.

Adding to 14040050251111 its reverse (11115205004041), we get a palindrome (25155255255152).

The spelling of 14040050251111 in words is "fourteen trillion, forty billion, fifty million, two hundred fifty-one thousand, one hundred eleven".