14040123535535 has 4 divisors (see below), whose sum is σ = 16848148242648. Its totient is φ = 11232098828424.

The previous prime is 14040123535511. The next prime is 14040123535547. The reversal of 14040123535535 is 53553532104041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14040123535535 - 2²² = 14040119341231 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14040123535492 and 14040123535501.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1404012353549 + ... + 1404012353558.

It is an arithmetic number, because the mean of its divisors is an integer number (4212037060662).

Almost surely, 2^{14040123535535} is an apocalyptic number.

14040123535535 is a deficient number, since it is larger than the sum of its proper divisors (2808024707113).

14040123535535 is an equidigital number, since it uses as much as digits as its factorization.

14040123535535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2808024707112.

The product of its (nonzero) digits is 540000, while the sum is 41.

Adding to 14040123535535 its reverse (53553532104041), we get a palindrome (67593655639576).

The spelling of 14040123535535 in words is "fourteen trillion, forty billion, one hundred twenty-three million, five hundred thirty-five thousand, five hundred thirty-five".