14041121020 has 12 divisors (see below), whose sum is σ = 29486354184. Its totient is φ = 5616448400.

The previous prime is 14041120991. The next prime is 14041121021. The reversal of 14041121020 is 2012114041.

It is a happy number.

It is a super-3 number, since 3×14041121020³ (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14041120985 and 14041121003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14041121021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 351028006 + ... + 351028045.

It is an arithmetic number, because the mean of its divisors is an integer number (2457196182).

Almost surely, 2^14041121020 is an apocalyptic number.

14041121020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

14041121020 is an abundant number, since it is smaller than the sum of its proper divisors (15445233164).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14041121020 is a wasteful number, since it uses less digits than its factorization.

14041121020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 702056060 (or 702056058 counting only the distinct ones).

The product of its (nonzero) digits is 64, while the sum is 16.

Adding to 14041121020 its reverse (2012114041), we get a palindrome (16053235061).

The spelling of 14041121020 in words is "fourteen billion, forty-one million, one hundred twenty-one thousand, twenty".