Search a number
-
+
1404332412103 = 2361057930961
BaseRepresentation
bin10100011011111000101…
…111000000110011000111
311222020211100012010121101
4110123320233000303013
5141002033044141403
62553050313200531
7203313444356065
oct24337057006307
94866740163541
101404332412103
114a1635043665
121a8204100147
13a257436422a
144bd81b6d035
15267e369771d
hex146f8bc0cc7

1404332412103 has 4 divisors (see below), whose sum is σ = 1465390343088. Its totient is φ = 1343274481120.

The previous prime is 1404332411983. The next prime is 1404332412127. The reversal of 1404332412103 is 3012142334041.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1404332412103 - 217 = 1404332281031 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1404332416103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30528965458 + ... + 30528965503.

It is an arithmetic number, because the mean of its divisors is an integer number (366347585772).

Almost surely, 21404332412103 is an apocalyptic number.

1404332412103 is a deficient number, since it is larger than the sum of its proper divisors (61057930985).

1404332412103 is an equidigital number, since it uses as much as digits as its factorization.

1404332412103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61057930984.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 1404332412103 its reverse (3012142334041), we get a palindrome (4416474746144).

The spelling of 1404332412103 in words is "one trillion, four hundred four billion, three hundred thirty-two million, four hundred twelve thousand, one hundred three".

Divisors: 1 23 61057930961 1404332412103