Base | Representation |
---|---|
bin | 1100110001110100011010… |
… | …0010110011011110000010 |
3 | 1211202011120011022011222112 |
4 | 3030131012202303132002 |
5 | 3320143421004212200 |
6 | 45514254002335322 |
7 | 2650036426504106 |
oct | 314350642633602 |
9 | 54664504264875 |
10 | 14050021554050 |
11 | 452764297a5a9 |
12 | 16aaba395a542 |
13 | 7abbb02cc541 |
14 | 36804b9ad906 |
15 | 1957175ee535 |
hex | cc7468b3782 |
14050021554050 has 48 divisors (see below), whose sum is σ = 27284926099392. Its totient is φ = 5372571969600.
The previous prime is 14050021554011. The next prime is 14050021554053. The reversal of 14050021554050 is 5045512005041.
It is a junction number, because it is equal to n+sod(n) for n = 14050021553998 and 14050021554016.
It is not an unprimeable number, because it can be changed into a prime (14050021554053) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1506584 + ... + 5510883.
It is an arithmetic number, because the mean of its divisors is an integer number (568435960404).
Almost surely, 214050021554050 is an apocalyptic number.
14050021554050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
14050021554050 is a deficient number, since it is larger than the sum of its proper divisors (13234904545342).
14050021554050 is a wasteful number, since it uses less digits than its factorization.
14050021554050 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7019243 (or 7019238 counting only the distinct ones).
The product of its (nonzero) digits is 20000, while the sum is 32.
Adding to 14050021554050 its reverse (5045512005041), we get a palindrome (19095533559091).
The spelling of 14050021554050 in words is "fourteen trillion, fifty billion, twenty-one million, five hundred fifty-four thousand, fifty".
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